Solve the problem.
A newspaper article about the results of a poll states: “In theory, the results of such a poll, in 99 cases out of 100 should differ by no more than 5 percentage points in either direction from what would have been obtained by interviewing all voters in the United States.” Find the sample size suggested by this statement. (Points : 5)
Use the confidence level and sample data to find a confidence interval for estimating the population mu. Round your answer to the same number of decimal places as the sample mean.
Test scores: n = 92, mean = 90.6, sigma = 8.9; 99% confidence (Points : 5)
88.4 < mu < 92.8
88.8 < mu < 92.4
88.2 < mu < 93.0
89.1 < mu < 92.1
Use the given information to find the minimum sample size required to estimate an unknown population mean mu.
Margin of error: $120, confidence level: 95%, sigma = $593 (Points : 5)
Assume that a sample is used to estimate a population mean mu. Use the given confidence level and sample data to find the margin of error. Assume that the sample is a simple random sample and the population has a normal distribution. Round your answer to one more decimal place than the sample standard deviation.
95% confidence; n = 91; x-bar = 16, s = 9.1 (Points : 5)
Use the given degree of confidence and sample data to construct a confidence interval for the population mean mu. Assume that the population has a normal distribution.
A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 225 milligrams with s = 15.7 milligrams. Construct a 95% confidence interval for the true mean cholesterol content of all such eggs. (Points : 5)
215.0 mg < mu < 235.0 mg
216.9 mg < mu < 233.1 mg
214.9 mg < mu < 235.1 mg
215.1 mg < mu < 234.9 mg
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